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n5stackexchange.
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provhttp://www.w3.org/ns/prov#
xsdhhttp://www.w3.org/2001/XMLSchema#
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isa:176191130
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prov:Entity
prov:value
Now, as I understand it, 'p' is a point in 3D space, (x,y,z), so how is it possible to square the point and have it equal the radius squared?
prov:wasQuotedFrom
n5:com
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