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n5stackexchange.
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provhttp://www.w3.org/ns/prov#
xsdhhttp://www.w3.org/2001/XMLSchema#
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prov:value
For the second part, divide the $k$ people into $k/2=n+1$ pairs and let the two people in each pair not be friends, while everybody is a friend with all those people they are not paired with.
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n5:com
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