"Not sufficient.Statement 2: \\(c =a+10\\) or \\(a = c-10\\).Now notice, b is a number between a and c and it can be written as \\(c-10<= b <=c\\)similarly d is a number between c and e or \\(c <= d <=c+4\\)If we add these two: \\(2c-10 <=b+d <= 2c+4\\)To find out the average, we need sum. lets just take a look at sum \\(Sum = a+b+c+d+e\\) or \\(Sum = c-10 + b + c + d +c+4\\)=>\\(Sum= 3c-6 + b +d\\)using b+d\\(3c-6" . . . . .