"For i = 0 to m???1 DMA get part of vector Y For j = 0 to n???1 DMA get sub-block of Matrix A DMA get part of vector X Compute AX and add to Y Endfor DMA put part of vector Y Endfor In the above routine, m and n are integers, A is an m by n matrix, and X and Y are vectors." . . . . . . .