Not sufficient.Statement 2: \(c =a+10\) or \(a = c-10\).Now notice, b is a number between a and c and it can be written as \(c-10<= b <=c\)similarly d is a number between c and e or \(c <= d <=c+4\)If we add these two: \(2c-10 <=b+d <= 2c+4\)To find out the average, we need sum. lets just take a look at sum \(Sum = a+b+c+d+e\) or \(Sum = c-10 + b + c + d +c+4\)=>\(Sum= 3c-6 + b +d\)using b+d\(3c-6