prov:value
| - So, INSUFFICIENTtaking both togethernow there are two approaches1. write the values of t from stat1 and then from stat2 and then take the common valuesfrom STAT1 t = 1,5,9,13,17,21,25,29,33from STAT2 t = 1,4,7,10,13,16,19,22,25,28,31,34common values are t = 1,13,25,2. equate t = 4k+1 to t=3s+1we have 4k + 1 = 3s+1k = 3s/4since, k is an integer so only those values of s which are multiple of 4 will
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