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  • = L(n,n) -> An AD(n) =/= L(n,n) ] -> SuperinfinityYour actual 'proof' is a specific example of the above 'proof'![ An AD(n) = (L(n,n) + 1) mod 9 -> An AD(n) =/= L(n,n) ] -> SuperinfinityDo you agree with the above version of Cantor's proof?> >>>> If you actually read my derivation of herc_cant_3 instead of blindly>> dismissing it,>> you will see it holds, just like all digits of PI appear in order b
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