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  • 17 Oct 2012, 22:43 I didn't check view all threads . however I will provide a method with which you can solve practically any problem whether speed or time is given.24km/hr --- 5 mins late30km/hr--- 4 mins early Diff in time = 9mins. (had he reached at 8:00am ideal time; 24km/hr --- reaches at 8:05 30km/hr --- reaches at 7:56.)lcm ( 24 and 30) =120.. hence if the distance was 120km.. 24km/hr would t
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