Subtracting this area from the total area of 4 and ???7 and subtracted twice this area from an area under D yields a 1:1:3 ratio of 4:???7:D. Such a ratio confirms the composition of the major component and indicates that the composition of the impurity is two Ds, one 4, one ???7 and one 5. [0069] Methods of identifying other types of properties may be easily identifiable to those of skill in the