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  • Hello Sharmila,Yes the above triangle can is an isolsceles triangle and the area can be calculated using the formula (1/2)*b*h where h=(hypotenuse^2(1/4)(base)^2). h=(2*sqrt(5))^2-((1/4)(2*sqrt(2))^2It would be great if you could highlight your doubt here. sharmila79 wrote:In the above question, two sides are same that is 2root5 and the third side is 2root 2.
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